Question

perfect squares cannot have2,_,_and8 in its ones place​

Answer 1

Answer:

3 and 7

Step-by-step explanation:

there exists no number which is a.perfect square and has last digits either 2 , 3 , 7 or 8

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Answer 2

Question

Perfect squares cannot have 2 , _ , _ and 8 in its ones place​.

$\rule{300}{1}$

Answer

Perfect Squares cannot have 2, 3, 7, and 8 in its ones place.

$\rule{300}{1}$

Additional Information

Square numbers are obtained after multiplying a number two times to itself.

Properties of square numbers are:

• When a number has its unit digit as 0, 1, 4, 5, 6 or 9 then it has a chance for being a perfect square.

• When a number has its unit digit as 3, 3, 7 or 8 then it is definitely not a perfect square.

• When a number has its unit digit as 1 or 9, it's square will end with 1.

Methods to find square root are:

• Prime Factorization Method
• Long Division Method

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