Perfectly Conical shaped hill has circumference of base equal to 2π kms. It’s slant height is 6 kms. Mathematician trekker wishes to complete one round around the hill. What is the minimum length that he needs to walk in kms before reaching the starting point on the circumference of the base.
Answers
Answered by
0
Let r m be the radius of the base, h m be the height and l m be the slant height of the cone.
Given, circumference =44 metres.
⇒2πr=44⇒2×
7
22
×r=44⇒r=7 metres.
It is also given that h=10 metres.
∴ Slant height l
2
=r
2
+h
2
⇒l=
r
2
+h
2
=
49+100
=
149
=12.2m.
Now, we know, the surface area of the tent =πrl.
=
7
22
×7×12.2m
2
=268.4m
2
∴ Area of the canvas used =268.4m
2
.
It is given that the width of the canvas is 2 m.
∴ Length of the canvas used =
width
area
=
2
268.4
=134.2m.
Answered by
0
Step-by-step explanation: circumference of cone=2*pi*radius
given circumference=2*pi kms
therefore 2pi=2pi*r
r = 1kms
slant height=6 kms
height of cone (h) =sqrt(35) kms
the minimum length to reach starting point= circumference of cone
=2pi kms
Similar questions