Question

Perfer the above attachment and answer ⬆️⬆️⬆️​

Answer 1

Answer:

0.75

Step-by-step explanation:

If a > 0 then a smallest/minimum value of a quadratic function ax² + bx + c is the y-coordinate of the vertex of a parabola. (In fact, if  a < 0, the vertex is the greatest/maximum value).

$y_{min} = c-\frac{b^2}{4a}$

~~~~~~~~~~~~

f(x) = x² - 3x + 3 ; a = 1, b = - 3, c = 3.

$y_{min} = 3 - \frac{(-3)^2}{4}$ = $\frac{3}{4} =$ 0.75

Answer 2

Answer:

0.75

Step-by-step explanation:

If a > 0 then a smallest/minimum value of a quadratic function ax² + bx + c is the y-coordinate of the vertex of a parabola. (In fact, if a < 0, the vertex is the greatest/maximum value).

y_{min} = c-\frac{b^2}{4a}y

min

=c−

4a

b

2

~~~~~~~~~~~~

f(x) = x² - 3x + 3 ; a = 1, b = - 3, c = 3.

y_{min} = 3 - \frac{(-3)^2}{4}y

min

=3−

4

(−3)

2

= \frac{3}{4} =

4

3

= 0.75