Question

perfom the multiplication

-3(a²-b²+3ab)​

Answer 1

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-3(a²-b²+3ab)​

$\huge✍︎\fbox\orange{ÂŇ}\fbox{SW} \fbox\green{ÊŘ}:$

$-3(a^2-b^2+3ab)$

$(-3)(a^2+-b^2+3ab)$

$=(-3)(a^2)+(-3)(-b^2)+(-3)(3ab)$

$=-3a^2+3b^2-9ab$

$\bold{=-3a^2-9ab+3b^2}$

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