Math, asked by ishratrafi99, 4 days ago

Perform the fllowing divisions & verify the result of (3p^2+6p+18)÷(p-6)

Answers

Answered by swatirayswatiray
3

answer is in attachment

hope it helps

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Answered by deepak9140
1

Answer:

[tex]According to question,

(3p²+6p+18)/p-6

⟹3[(p−6)(p+8)+54]/p-6

⟹3(p+8)+{ 162/p-6 }

Here, Numerator is not completely divisible by denominator.

Hence, remainder is 162

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