Question

Perform the following binary arithmetic:
a. (1 1001 01 )2 + (101010)​

Answer 1

Answer:

10001111

Explanation:

Number 1 in the decimal system

11001012 = 10110

Number 2 in the decimal system

1010102 = 4210

Their sum

101 + 42 = 143

Result in binary form

14310 = 100011112

Answer 2

Answer:

1100101

1×2×0+0×2×1+1×2×2+0×2×3+0×2×4+1×2×5+1×2×6

1×1+0×2+1×4+0×8+0×16+1×32+1×64

1+0+4+0+0+32+64

101

101010

0×2×0+1×2×1+0×2×2+1×2×3+0×2×4+1×2×5

1×1+1×2+0×4+1×8+0×16+1×32

1+2+0+8+0+32

42

101+42

143

Explanation

divide the no in prime factors and get the result ok .

I hope this answers is right