Chemistry, asked by nagromita8, 3 months ago

perform the following reaction and classify as physical and chemical change
i) Fe with CuSO4 solution in water
ii) Zn with dilute H2SO4
iii) Heating of CuSo4 crystals ​

Answers

Answered by saiyedfazil
3

1) iron displace copper from copper sulphate solution in water and form iron sulphate and copper

2)Zinc displace Hydrogen from sulphuric acid and form zinc sulphate and Hydrogen gas

3) the water of copper sulphate evaporate and copper sulphate crystal turn blue to white

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Answered by jainani420
2

Answer:

a) Reaction of Iron Nails with Copper Sulphate Solution in Water

Fe+CuSO4 = FeSO4 + Cu

When an iron nail is dipped in copper sulphate solution, a brown coating of copper is formed on the surface of iron and the colour of copper sulphate solution changes from blue to light green. This reaction shows that iron is more reactive than copper as it displaces copper from its solution and iron passes into solution as Fe2+ ions and ferrous sulphate solution is formed.

This reaction is a single displacement reaction.

b) When zinc is added to copper sulphate (CUSO4) solution due to more reactivity of zinc, cooper is replaced by the zinc and forms zinc sulphate. During the process, the colour of the solution changes from blue to colourless

CuSO4 (aq) + Zn (S) = Cu (S) + ZnSO4 (aq) is an example of metal displacement reaction.

c) Copper sulphate pentahydrate contain 5 moles of water per one mole of copper (II) sulphate. Its formula is written as CuSO4.5H2O. It can be converted into anhydrous copper sulphate when heated strongly. The blue colour of copper sulphate is due to water of hydration. When heated, it loses two water molecules at ~63°C followed by two more at ~109°C and the final water molecule at ~200°C and turns to white coloured anhydrous copper sulphate.

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