perimeter and area for class 6
Answers
Answer:
1) Area - length multiplied to Breadth = 150metre square
2) First we need to find the Area = 150 multiplied to 80 = 12000m....
Cost of 1 Meter = 40 rupee
Then, Cost of 12000m = 12000 multiply to 40 = 480000 rupee....
Sorry Friend i don't know 3 rd question....
Answer:
HERE IS YOUR ANSWER!!
Step-by-step explanation:
1. the dimensions of outer rectangle are
l=15m
b=10m
area of outer rectangle= l*b(lxb)
=15mx10m
=150m^2(150 meter square)
Now,
dimensions of inner rectangle are
l=9m
b=6m
area of inner rectangle=l*b
=9mx6m
=54m^2
Now,
difference between area of outer rectangle and area of of inner rectangle= area of shaded region
= 150m^2- 54m^2
= 96m^2
There fore area of shaded region is 96m^2.
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2. The dimensions of field are
l=150m
b=80m
area of rectangular field = l*b
=150m*80m
=12000m^2
Now,
the cost of fencing per meter= 40 rupees
Then,
here we have 12000m
area of field*cost per meter
12000m*40 rupees
4,80,000 rupees
Therefore the cost for fencing is rupees 4,80,000
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3. The dimensions of sheet of paper are
l=8m
b=9m
let's convert m into cm
now, 1m =100cm
l=8*100cm = 800cm
b=9*100cm= 900cm
now,
the dimensions of each greeting card are
l=24cm
b=12 cm
now,
we need to find areas of both paper sheet and greeting card
area of paper sheet= l*b
= 800cm*900cm
=7,20,000cm^2
area of each greeting card=l*b
= 24cm * 12cm
=288 cm^2
now,
we need to divide both areas
720000cm^2 (divided by) 288cm^2
(cm^2 gets cancelled in both the equations)
= 2,500 cards
Therefore, the number of cards we can make of out the sheet= 2,500 cards
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