Question

perimeter of a recatangular field js 100cm. and length is 40 cm. find the breath​

Answer 1

Given:-

• Perimeter of a rectangular field i.e. 100 cm.
• Length of the field i.e. 40 cm.

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To find:-

• Breadth of the rectangular field.

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Solution:-

Let the breadth of the rectangular field be x

Perimeter of the field= 100 cm

Length of the field= 40 cm

Perimeter of rectangle:- 2(l+b)

Putting values:-

100= 2(40+x)

100= 80+2x

100-80= 2x

20= 2x

x= 20÷2

x= 10

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So the breadth we found is 10 cm.

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Answer 2

Step-by-step explanation:

$\frak Given = \begin{cases} &\sf{Perimeter\ of\ the\ rectangular\ field\ =\ 100cm.} \\ &\sf{Length\ of\ the\ rectangular\ field\ =\ 40cm.} \end{cases}$

To find:- We have to find the breadth of the rectangular field ?

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$\frak{\underline{\underline{\dag As\ we\ know\ that:-}}}$

$\sf : \implies {\pink{\underline{Perimeter_{(rectangle)}\ =\ 2(l\ +\ b).}}}$

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$\frak{\underline{\underline{\dag By\ substituting\ the\ values,\ we\ get:-}}}$

$\sf : \implies {Perimeter\ =\ 2(l\ +\ b)} \\ \\ \sf : \implies {100\ =\ 2(40\ +\ b)} \\ \\ \sf : \implies {\cancel \dfrac{100}{2}\ =\ 40\ +\ b} \\ \\ \sf : \implies {50\ =\ 40\ +\ b} \\ \\ \sf : \implies {50\ -\ 40\ =\ b} \\ \\ \sf : \implies {10\ =\ b} \\ \\ \sf : \implies {\purple{\underline{\boxed{\bf Breadth\ =\ 10cm.}}}}\bigstar$

Hence:-

$\sf \therefore {\underline{The\ required\ breadth\ of\ the\ rectangular\ field\ is\ 10cm.}}$

$\bf{\underline{\underline{More\ to\ know:-}}}$

$\sf : \implies {Perimeter_{(parallelogram)}\ =\ 2(Base\ +\ Height).}$

$\sf : \implies {Perimeter_{(triangle)}\ =\ a\ +\ b\ +\ c\ [a,\ b,\ and\ c\ being\ the\ length\ sides].}$

$\sf : \implies {Perimeter_{(square)}\ =\ 4a\ [a\ =\ length\ of\ a\ side].}$

$\sf : \implies {Perimeter_{(rhombus)}\ =\ 4\ ×\ a\ [a\ =\ length\ of\ a\ side].}$