Math, asked by beherags, 7 hours ago

Perimeter of a rectangle 4.8m less than two-fifth of the perimeter of a square. If the perimeter of the square is 80m, find the length and breadth of the rectangle given that breadth is one-third of the length

Answers

Answered by krishnapratapsomvans
0

Answer:

l=P

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Answered by VεnusVεronίcα
28

Answer:

The length and breadth of the rectangle are 10.2m and 3.4m respectively.

Step-by-step explanation:

Given, breadth of the rectangle is ⅓ of the length :

Breadth = ⅓ × Length

Let the :

Length of the rectangle be x.

Breadth of the rectangle be ⅓x.

Also, perimeter of rectangle is 4.8m less than ⅖ of the perimeter of a square having perimeter 80m :

P of rectangle = (⅖ × 80) – 4.8

➺ P = (2 × 16) – 4.8

➺ P = 32 – 4.8

P = 27.2 m

Therefore,the perimeter of the rectangle is 27.2m.

Now, let's find the length and breadth of the rectangle :

P of rectangle = 2 (L + B)

➺ 27.2 m = 2 (x + x/3)

➺ 27.2 m = 2 [ (3x + x)/3 ]

➺ 27.2 m = 2 [4x/3]

➺ 27.2 m = 8x/3

➺ 27.2 m × 3 = 8x

➺ 81.6 m = 8x

➺ 81.6/8 = x

10.2m = x

Substituting these values for knowing length and breadth :

Length : x = 10.2m

Breadth : ⅓x = 3.4m

Therefore, the length and breadth of the rectangle are 10.2m and 3.4m.

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