Perimeter of a rectangle 4.8m less than two-fifth of the perimeter of a square. If the perimeter of the square is 80m, find the length and breadth of the rectangle given that breadth is one-third of the length
Answers
Answer:
l=P
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Answer:
The length and breadth of the rectangle are 10.2m and 3.4m respectively.
Step-by-step explanation:
Given, breadth of the rectangle is ⅓ of the length :
➺ Breadth = ⅓ × Length
Let the :
➺ Length of the rectangle be x.
➺ Breadth of the rectangle be ⅓x.
Also, perimeter of rectangle is 4.8m less than ⅖ of the perimeter of a square having perimeter 80m :
➺ P of rectangle = (⅖ × 80) – 4.8
➺ P = (2 × 16) – 4.8
➺ P = 32 – 4.8
➺ P = 27.2 m
Therefore,the perimeter of the rectangle is 27.2m.
Now, let's find the length and breadth of the rectangle :
➺ P of rectangle = 2 (L + B)
➺ 27.2 m = 2 (x + x/3)
➺ 27.2 m = 2 [ (3x + x)/3 ]
➺ 27.2 m = 2 [4x/3]
➺ 27.2 m = 8x/3
➺ 27.2 m × 3 = 8x
➺ 81.6 m = 8x
➺ 81.6/8 = x
➺ 10.2m = x
Substituting these values for knowing length and breadth :
➺ Length : x = 10.2m
➺ Breadth : ⅓x = 3.4m
Therefore, the length and breadth of the rectangle are 10.2m and 3.4m.