Question

perimeter of a rectangle field in 36 and its length is 10 then find its area ?
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Answer 1

★ Given :-

• Perimeter of Rectangle = 36 cm .
• Length of Rectangle = 10 cm .

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★ To Find :-

• Area of Rectangle = ?

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★ Solution :-

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∓ Here, it is given that, Perimeter of Rectangle is 36 cm . Length of Rectangle is 10 cm . And, we have to find the Area of Rectangle .

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• Now, let's solve step by step -----

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◆ First, we will find Breadth of Rectangle :-

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$\bullet \: \sf{Perimeter\:_{Rectangle} =2 \: ( \: Lenght +Breadth \: )} \\ \\ \dashrightarrow \: \sf{36 = 2 \: ( \: 10 +Breadth \: )} \\ \\ \dashrightarrow \: \sf{ \frac{36}{2} = 10 + Breadth } \\ \\ \dashrightarrow \: \sf{18 = 10 + Breadth} \\ \\ \dashrightarrow \: \sf{Breadth = 18 - 10} \\ \\ \dashrightarrow \: \sf{Breadth = 8 \: cm}$

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◆ Now, we will find Area of Rectangle :-

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$\bullet \: \sf{Area\:_{Rectangle}=Lenght \times Breadth} \\ \\ \dashrightarrow \: \sf{Area = 10 \times 8} \\ \\ \dashrightarrow \: \sf{Area = 80 \: {cm}^{2} }$

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★ Hence :-

• Area of Rectangle = 80 cm² .

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Answer 2

As per the data given in the question,

We have to determine the area of rectangle.

As we know that,

$Area = l\times b\\Perimeter = 2(l+b)$

From the data it is given that,

Perimeter of rectangle = 36 units.

Length of rectangle = 10 units.

So, let the breadth of rectangle will be x units.

So, breadth of rectangle will be

$Perimeter = 2(l+b)\\=>36 = 2(10+b)\\=>10+b = \frac{36}{2}\\10+b = 18\\=>b = 18-10 = 8\:units$

Hence, area of rectangle will be,

$Area = l\times b \\Area = 10 \times 8\\Area = 80\:unit^2$

Hence, area of rectangle will be $80\:units^2$