perimeter of a rectangle is 100 M if the length is decreased by 2 metre and the breadth is increased by 3 metre the area is increased by 44 m sq find length & breadth of the rectangle
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perimeter of rectangle = 100 m
⇒ 2(x+y) = 100
⇒ x+y = 50 --------- eq.1
Original area = xy
decreased length = x-2
increased breadth=y+3
new area= xy+44
⇒(x-2)(y+3)=xy +44
⇒ xy+3x-2y-6=xy+44
⇒3x-2y=50
⇒3x-2y=x+y [from eq.1]
⇒2x=3y
⇒x=(3/2)y
from eq.1
x+y=50
⇒(3/2)y+y=50
⇒ 5y/2=50
⇒ 5y=100
⇒ y=20
∴x=30
Hope it helps u :-)
⇒ 2(x+y) = 100
⇒ x+y = 50 --------- eq.1
Original area = xy
decreased length = x-2
increased breadth=y+3
new area= xy+44
⇒(x-2)(y+3)=xy +44
⇒ xy+3x-2y-6=xy+44
⇒3x-2y=50
⇒3x-2y=x+y [from eq.1]
⇒2x=3y
⇒x=(3/2)y
from eq.1
x+y=50
⇒(3/2)y+y=50
⇒ 5y/2=50
⇒ 5y=100
⇒ y=20
∴x=30
Hope it helps u :-)
PurvaSharma:
thank you so much
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