Question

Perimeter of a rectangle is 13 cm. if its breadth is 11/4 cm. Then, find its length.

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Answer 1

*Question:-

Perimeter of a rectangle is 13 cm. if its breadth is 11/4 cm. Then, find its length.

*Answer:-

• Perimeter of a rectangle = 13 cm
• 2(Length + Breadth) = 13
• Length + 11/4 = 13/2
• Length = 13/2 - 11/4
• Length = 26/4 - 11/4
• Length = (26 - 11)/4
• Length = 15/4

Therefore the length of rectangle is 15/4 cm

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Answer 2

Given :-

• Perimeter of a rectangle = 13 cm.

• The bradth of a rectangle (b) = ${\sf {\dfrac {11}{4}}}$ cm.

To Find :-

• The length of the rectangle.

We know that,

$\rightsquigarrow{\underline {\boxed {\bf {\pink {Perimeter~ of~ a~ rectangle = 2 (l + b)}}}}}$

Where,

• l = Length
• b = Breadth

Solution :-

Let,

• The length of the rectangle be "x"

Given,

★ Perimeter of a rectangle = 13 cm.

★ Breadth of a rectangle = ${\sf {\dfrac {11}{4}}}$ cm.

Therefore,

$\qquad$ $\rightsquigarrow{\sf {2 (l + b)}}$

$\qquad$ $\rightsquigarrow{\sf {2 (x + {\dfrac {11}{4}}) = 13 }}$

$\qquad$ $\rightsquigarrow{\sf {2x + {\dfrac {22}{4}} = 13}}$

$\qquad$ $\rightsquigarrow{\sf {2x = 13 - {\dfrac {22}{4}}}}$

$\qquad$ $\rightsquigarrow{\sf {2x = {\dfrac {13 \times 4 - 22}{4}}}}$

$\qquad$ $\rightsquigarrow{\sf {2x = {\dfrac {52 - 22}{4}}}}$

$\qquad$ $\rightsquigarrow{\sf {2x = {\dfrac {30}{4}}}}$

$\qquad$ $\rightsquigarrow{\sf {x = {\dfrac {30}{4 \times 2}}}}$

$\qquad$ $\rightsquigarrow{\sf {x = {\dfrac {{\cancel{{30}}^{15}}}{{\cancel{{8}}^{4}}}}}}$

$\qquad$ ${\red {\rightsquigarrow}} ~{\sf {\red {x = {\dfrac {15}{4}}~cm}}}$

Hence,

${\bf {\color{magenta} {The~ length~ of~ the~ rectangle~ is~ {\dfrac {15}{4}} ~cm}}}$