Question

perimeter of a rectangle is 13 cm if its widrh is 11/4 cm find its length​

Answer 1

Answer:

15/4cm .

Step-by-step explanation:

Perimeter of the rectangle =13cm

Width = 11/4 cm

perimeter= 2(L+B)

13=2(l+ 11/4)

13= 2l+22/4

2l+22/4= 13

2l= 13/-22/4

2l = 52-22/4

2l = 30/4

l= 30/4

l = 15/4cm

Answer 2

Answer :-

• The length of the rectangle = 15/4 cm.

To find :-

• The length of the rectangle.

Solution :-

• Here, the perimeter and width of a rectangle is given to us. We have to find it's length.

Let :-

• The length of the rectangle be "x" cm.

We know that :-

$\underline{ \boxed{\sf Perimeter \: of \: a \: rectangle = 2 \: (L + W)}}$

Where,

• L = Length.
• W = Width.

Here,

• Perimeter = 13 cm.
• Length = "x" cm.
• Width = 11/4 cm.

-----------------------------------------------------------

Therefore,

$\longmapsto \sf2 \: \left(x + \dfrac{11}{4}\right) = 13$

$\longmapsto\sf2x + \dfrac{22}{4} = 13$

$\longmapsto\sf2x = 13 - \dfrac{22}{4}$

$\longmapsto\sf2x = \dfrac{13 \times 4 - 22 \times 1}{4}$

$\longmapsto \sf2x = \dfrac{52 - 22}{4}$

$\longmapsto \sf2x = \dfrac{30}{4}$

$\longmapsto\sf x = \dfrac{ \frac{30}{4} }{2}$

$\longmapsto\sf x = \dfrac{30}{4} \times \dfrac{1}{2}$

$\longmapsto\sf x = \cancel{\dfrac{30}{8}}$

$\longmapsto \overline{ \boxed{\sf x = \dfrac{15}{4} \: cm}}$

Hence :-

• The length of the rectangle is 15/4 cm.

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