Question

Perimeter of a rectangle is 2.4m less than 2/5 of the perimeter of a square . If tge perimeter of tge square is 40 m, find the length and breadth of the rectangle that breadth is 1/3 of the length​

Answer 1

Answer:

Length of the rectangle=5.1m and Breadth of the rectangle =1.7 m

Step-by-step explanation:

Let the length of the rectangle be a and breadth be b.

Given,

Perimeter of the square=40m;

b= a/3 ( breadth of the rectangle =1/3 of the length)

According to the question,

2(a+b) =2/5 (4c) -2.4 Here, 4c=perimeter of square

c=side of the square

or, 2(a+a/3) =2/5 ×40 -2.4

solve the equation...

you will get the value of a

a=5.1

From that, b=a/3

b=5.1/3 =1.7

Answer 2

☢️$\large\rm\blue{CORRECT\:QUESTION}$☢️

• Perimeter of a rectangle is 2.4m less than 2/5m of the perimeter of square .if the perimeter of the square is 40m,Find the length and Breadth of the rectangle which is 1/3 of the length.

☢️$\huge\rm\blue{GIVEN}$☢️

• Perimeter of rectangle is 2.4m less than 2/5 of Perimeter of square.

• The perimeter of square is 40m.

• Breadth of rectangle is 1/3 of length.

☢️$\huge\rm\blue{To\:Find}$☣️

• The length and Breadth of Rectangle.

Now,

Atq.

Perimeter of Rectangle= $\tt{\dfrac{2}{5}\times{40}-2.5}$

Perimeter of Rectangle=16-2.5=13.6m.

Now,

Atq.

Let the length of Rectangle be x

Breadth of Rectangle =$\tt\blue{\dfrac{1}{3}\times{x}}=\dfrac{x}{3}}$

Perimeter of Rectangle= 2(L+B)

↪️$\implies\tt{13.6=2(x+\dfrac{x}{3})}$

↪️$\implies\tt{13.6=2(3x+\dfrac{x}{3})}$

↪️$\implies\tt{13.6=2(\dfrac{4x}{3})}$

↪️$\implies\tt{13.6\times{3}=2\times{4x}}$

↪️$\implies\tt{40.8=2\times{4x}}$

↪️$\implies\tt{\dfrac{40.8}{2}=4x}$

↪️$\implies\tt{20.4=4x}$

↪️$\implies\tt{x=\dfrac{\cancel{20.4}}{\cancel{4}}}$

↪️$\implies\tt{x=5.1m}$

Hence, The length of Rectangle is 5.1m

Breadth of Rectangle=1/3×5.1=1.7m

Hence, The length and Breadth of Rectangle is 5.1m and 1.7m respectively.

$\rm\red{VERIFICATION}$

Perimeter of Rectangle=2(L+B)

13.6=2(5.1+1.7)

13.6=2×6.8

13.6=13.6

Hence, Verified ✔️