Question

perimeter of a rectangle is 220m.
if one side exceeds the other by 50m , find the length of sides.​

Answer 1

Answer:

length = 80 m

breadth = 30 m

Step-by-step explanation:

let the breadth of rectangle be x

and the length be ( x + 50 )

Perimeter of rectangle = 2 × ( length + breadth ) = 220 m

$220 = 2 \times ({(x + 50) + x})$

$110 = x + 50 + x$

$2x = 110 - 50$

$x = 55 - 25$

$x = 30$

breadth of the rectangle = 30 m

length of the rectangle = 30 + 50 m = 80 m