Question

Perimeter of a rectangle is 52 its breadth is twice its length find the dimensions of the rectangle

Answer 1

let the length the x

breadth be 2x

$perimeter \: of \: rectangle = 2{length + breadth}$

• 52=2(X+2X)
• 52=2(3x)
• X=52/6
• X=8.66 cm (approx)

length is 8.66cm

breadths is 17.33cm