Perimeter of a rectangle is 60 cm. What is the maximum area of such rectangle if we consider all such rectangles formed with given perimeter?
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Answer:
2(l+b)= 60
l+b= 30
Step-by-step explanation:
l= 30-b
the max area is when l and b are equal
a=15*15=225 but then the given fig would be square.
for a rectangle the l and b should be 16 and 14 for max area
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