Question

Perimeter of a rectangle is 60cm. If its breadth is 10cm, what is its length.​

Answer 1

Given -

• Perimeter of a rectangle is 60cm.
• Breadth of the rectangle is 10cm.

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To find -

• Length of the rectangle.

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Solution -

We have breadth and perimeter of the rectangle and need to find the length.

• Let the length of the rectangle be L.

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Perimeter of a rectangle is given by

$\: \: \: \: \: \: \: \boxed{\bf{\bigstar{Perimeter_{(Rectangle)} = 2(Length + Breadth){\bigstar}}}}$

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$\tt\dashrightarrow{Perimeter = 2(L + B)}$

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$\tt\dashrightarrow{60 = 2(L + 10)}$

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$\tt\dashrightarrow{\dfrac{60}{2} = L + 10}$

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$\tt\dashrightarrow{30 = L + 10}$

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$\tt\dashrightarrow{L = 30 - 10}$

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$\bf\dashrightarrow{L = 20cm}$

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Hence,

• Length of the rectangle is 20cm.

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Answer 2

$\green\bigstar$Question Given :

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• Perimeter of a rectangle is 60cm. If its breadth is 10cm, what is its length.

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$\pink\bigstar$Required Solution :

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☯ Value Given to us :

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• Perimeter of rectangle = 60 cm

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• Breath of rectangle = 10 cm

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$\purple\bigstar$Required Diagram :

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$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 20cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 10cm}\put(-0.5,-0.4){\bf }\put(-0.5,3.2){\bf }\put(5.3,-0.4){\bf }\put(5.3,3.2){\bf }\end{picture}$

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☯ Formulated used Here :

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• $\longrightarrow$Perimeter = 2 ( l + b)

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☯ Putting Vlaue in Formula :

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• $\longrightarrow$P = 2 ( l + b) cm

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• $\longrightarrow$60 = 2 ( l + 10 ) cm

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• $\longrightarrow$30 = l + 10 cm

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• $\longrightarrow$l = 20 cm

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• Length of rectangle 20 cm

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$\red\bigstar$Note :

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• $\longrightarrow$Kindly view answer from brainly.in for clear view of diagram !

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