Question

perimeter of a rectangle is 70. if weidth is 11 find the length?​

Answer 1

Answer:

perimeter of rectangle= 2(l+b)

= 70= 2(l+11)

=11+l = 70/2

length= 35-11

length= 24

Answer 2

$\large {\red {\underline {\overline {\mid {\sf {Aim:-{\mid }}}}}}}$

To find the length of a rectangle whose width is 11 units and perimeter is 70 units.

$\large {\red {\underline {\overline {\mid {\sf {Prerequisite \: Knowledge :-{\mid }}}}}}}$

$\small{\orange {\boxed {\bf {Perimeter = 2(length + width)}}}}$

$\large {\red {\underline {\overline {\mid {\sf {Calculation:-{\mid }}}}}}}$

$⇒ Perimeter = 2(length + width) \\⇒ 70 = 2(length + 11) \\ ⇒\frac{70}{2} - 11 = length \\⇒ 35 - 11 = length \\ ⇒{\orange{\boxed{Length = 24 units}}}$