Question

Perimeter of a rectangle is equal to the perimeter of square whose area is 400 cm^2.Find the area of rectangle if length of rectangle is 40% more than the side of square​

Answer 1

Answer:

Given here,

Perimeter= 82

2*(l+b)=82 => l+b=41 —(1)

Area=400 m^2

l*b=400 —(2)

Replacing equation (1) in equation (2), we get

(41-b)*b=400 => 41b-b^2=400 => b^2–41b+400=0

Solving this, we get b=25,16

Corresponding l=16,25

As we know breadth is smaller than length, hence breadth = 16