Perimeter of a rectangle whose length (L) is 4 cm more than twice its breadth (b) is 14 cm. The pair of linear equations representing the above information is
Answers
Answer:
b
Step-by-step explanation:
l-b=4
2(l+b)=14
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The pair of linear equations are
l = 2b + 4
2 ( l + b ) = 14
Given :
Perimeter of a rectangle whose length (l) is 4 cm more than twice its breadth (b) is 14 cm
To find :
The pair of linear equations representing the above information
Solution :
Step 1 of 3 :
Form the first equation
Length of the rectangle = l cm
Breadth of the rectangle = b cm
Since length (l) is 4 cm more than twice its breadth (b) is 14 cm
So by the given condition
l = 2b + 4
Step 2 of 3 :
Form the second equation
Perimeter of the rectangle
= 2 ( Length + Breadth )
= 2 ( l + b )
Since Perimeter of the rectangle is 14 cm
2 ( l + b ) = 14
Step 3 of 3 :
Write down the pair of linear equations
The pair of linear equations obtained are
l = 2b + 4
2 ( l + b ) = 14
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