Question

perimeter of a rectangle with breadth 6 cm is 34 what will be the area of the square with the side equal to the twice of length of the given rectangle?

Answer 1

perimeter=34
breath =6
perimeter=2(l+b)
34=2(l+6)
34/2=l+6
17=l+6
l=17-6
if,l=11
then , side of square =2×11=22
so,
area of square=side×side
= 22×22
=484

Answer 2

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According to the question
first we have to find the lenght

let the X be the lenght of the rectangle

perimeter = 2 (l + b)
=34=2 (X + 6)
=34 = 2X +12
=34- 12 =2X
=22=2X
= 22/2= X
= 11 = X
so the lenght of the rectangle is 11 cm

As it is given that the side of an square is twice the lenght of rectangle

So side of a square =(2 ×11 )cm=22 cm

Area of the Square = (side)^2 = (22)^2 cm^2

= 484 cm^2

So the area of the Square is 484 cm^2