Question

Perimeter of a rectangte is 24 meters. lf length of a rectangle is 2 meters more

than its breadth, then find the breadth of a rectangle.​

Answer 1

We Have :-

Perimeter of a rectangle is 24 meters.

The length of a rectangle is 2 meters more than its breadth.

To Get :-

The breadth of a rectangle.

Solving to get Results :-

Consider ,The breadth of a rectangle = x

The length of a rectangle = ( x + 2 )

We know, Perimeter of a rectangle is 2 ( l + b )

The Perimeter of a rectangle is 24 meters.

=> 2 ( x + x + 2 ) = 24

=> 2 ( 2 x + 2 ) = 24

=> 4x + 4 = 24

=> 4x = 24 - 4

=> 4x = 20

=> x = 20/4

=> x = 5

• The breadth of a rectangle = x = 5m

• The length of a rectangle = ( x + 2 ) = 5 + 2 = 7m

Answer 2

Given:

• Perimeter of rectangle = 24m

• Length of rectangle is 2 m is more than breadth

To find:

• Breadth of rectangle

Let:

• Breadth of rectangle = x

• Length of rectangle = 2x

Solution:

we know:

$\bigstar \boxed{\rm{}Perimeter \: of \: rectangle = 2(length + breadth)}$

By using this formula we can find value of x.

$\dashrightarrow\sf{}Perimeter \: of \: rectangle = 2(length + breadth)$

$\dashrightarrow\sf{}24= 2(2+x+x)$

$\dashrightarrow\sf{}24= 4 + 2x + 2x$

$\dashrightarrow\sf{}24= 4 +4x$

$\dashrightarrow\sf{}4+4x=24$

$\dashrightarrow\sf{}4x=24-4$

$\dashrightarrow\sf{}4x=20$

$\dashrightarrow\sf{}x = \frac{20}{4}$

$\dashrightarrow\sf{}x = \frac{5\times 4}{4}$

$\dashrightarrow\sf{}x = \frac{\cancel4 \times 5}{\cancel4}$

$\dashrightarrow\sf{}x =5$

Verification:

$\dashrightarrow\sf{}24= 2(2+x+x)$

$\dashrightarrow\sf{}24= 2(2+5+5)$

$\dashrightarrow\sf{}24=2(12)$

$\dashrightarrow\sf{}24=24$

LHS = RHS

Hence verified!

.°. breadth of rectangle = 4m