Math, asked by parulpatni20, 4 months ago

Perimeter of a rectangular field is 100
m.If its length is 35 m, what will be its
area?
Answer:​

Answers

Answered by rscs988619
1

Answer:

525m

Step-by-step explanation:

p=2(l+b) , area=l×b

Answered by DüllStâr
56

Diagram:

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 35 cm(length)}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 15 cm(Breadth)}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

Question:

Perimeter of a rectangular field is 100m. If its length is 35 m, what will be its area?

Given

  • Perimeter of rectangle = 100m
  • Length of rectangle = 35m

To find:

  • Area

Let:

  • Breadth of rectangle = x

Solution:

So to Area first we should know value of breadth of rectangle:

We know:

 \bigstar \boxed{ \boxed{ \rm \: perimeter \: of \: rectangle = 2(length + breadth)}}

By using this formula we can find value of breadth.

 : \implies \sf perimeter \: of \: rectangle = 2(length + breadth) \\

 : \implies \sf 100= 2(35+ x) \\

 : \implies \sf  \dfrac{100}{2} = (35+ x) \\

 : \implies \sf  \cancel \dfrac{100}{2} = (35+ x) \\

 : \implies \sf  50 = (35+ x) \\

 : \implies \sf  x = 50 - 35 \\

 : \implies\underline{ \boxed{\sf{}x = 15 \: m}} \\

Verification:

 : \implies \sf 100= 2(35+ x) \\

put value of breadth in this equation

 : \implies \sf 100= 2(35+ 15) \\

 : \implies \sf 100= 2(50) \\

 : \implies \sf 100= 2 \times 50 \\

 : \implies \underline{ \boxed{\sf 100=100}} \\

Now Let's find Area of rectangle

We know:

 \bigstar \boxed{ \boxed{ \rm \: area\: of \: rectangle = length  \times breadth}}

By using this formula we can find value of Area

 : \implies \sf \sf\: area\: of \: rectangle = length  \times breadth \\

 : \implies \sf \sf\: area\: of \: rectangle = 35\times 15\\

 : \implies \underline{ \boxed{\sf\: area\: of \: rectangle = 525 \:  {m}^{2} }}\\

.°. Area of rectangle =525m²

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