Question

Perimeter of a rectangular plot is 860 m. Its length is 4 more than its breadth. Find its length and breadth.


pls fast​

Answer 1

let breadth be x and length be y

perimeter=2(length + breadth)

860=2(x+4+x)

860=2(2x+4)

2x+4= 430

2x= 426

x=218m

breath = 218m

length= breadth+4=222m

hope this helps..

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Answer 2

Gɪᴠᴇɴ :-

• Perimeter of a rectangular plot is 860 m.

• The length is 4 more than its breadth.

Tᴏ Fɪɴᴅ :-

• Length of Rectangular plot.

• Breadth of Rectangular plot.

$\large\underline{\sf{Solution-}}$

Given that,

Length of the rectangular plot is 4 more than its breadth.

$\begin{gathered}\begin{gathered}\bf\: Let-\begin{cases} &\sf{Breadth_{(rectangle)} = x \: m} \\ &\sf{Length_{(rectangle)} =( 4 + x )\: m} \end{cases}\end{gathered}\end{gathered}$

it is given that

• Perimeter of Rectangular plot = 860 m

We know that,

$\red{ \boxed{ \bf \: Perimeter_{(rect.)}= 2(Length_{(rect.)}+Breadth_{(rect.)}}}$

So,

On substituting the values, we get

$\rm :\longmapsto\:860 = 2(x + 4 + x)$

$\rm :\longmapsto\:860 = 2(2x + 4)$

$\rm :\longmapsto\:860 = 4x \: + \: 8$

$\rm :\longmapsto\:4x = 860 - 8$

$\rm :\longmapsto\:4x = 852$

$\rm :\longmapsto\:x = \dfrac{ \cancel{852}}{ \cancel{4}} = 213$

$\begin{gathered}\begin{gathered}\bf\: Hence-\begin{cases} &\sf{Breadth_{(rectangle)} = 213 \: m} \\ &\sf{Length_{(rectangle)} =217\: m} \end{cases}\end{gathered}\end{gathered}$

Additional Information :-

$\blue{ \boxed{ \sf \: Area_{(rectangle)} = Length_{(rectangle)} \times Breadth_{(rectangle)}}}$

$\blue{ \boxed{ \sf \: Area_{(square)} = {side}^{2}}}$

$\blue{ \boxed{ \sf \: Area_{(rhombus)} = base \times height}}$

$\blue{ \boxed{ \sf \: Area_{(parallelogram)} = base \times height}}$

$\blue{ \boxed{ \sf \: Perimeter_{(square)} = 4 \times side}}$

$\blue{ \boxed{ \sf \: Perimeter_{(rhombus)} = 4 \times side}}$