perimeter of a rhombus is 104 CM and the length of one of its diagonal is 48 cm find the length of its other diagonal
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Point o is bisector that divide diagonals into 2 parts.
Then Use Phythagoras theroem
In which Hypotenuse and one side is given find other.
Then Use Phythagoras theroem
In which Hypotenuse and one side is given find other.
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Answer: 20 cm
Step-by-step explanation:
as we know that each sides of a rhombus are equal to each other and it has four sides in all, so here the length of a single side is =(104/4)=26 cm.
And we also know that diagonals of a rhombus intersects each other in half of their length. So half of it will be =(48/2)=24
now applying pythagoras theorem (as two diagonals of a rhombus intersects in 90 degree.),
s=√((26)^2-(24)^2)=10 cm
so the other diagonal will be (10*2)=20 cm (ans)
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