perimeter of a rhombus is 180 cm and one of its diagonal is 72 cm find the length of the diagonal and also its area .
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Answered by
0
Answer:
Rhombus
p=54cm
q Diagonal
72
cm
P Perimeter
180
cm
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Answered by
0
Answer:
the given perimeter is 180
and the given diagonal is 72
P=4a
a=root (p^2+q^2)
p=root(1/4*p^2-q^2
= root(1/4.180^2-72^2=54 cm
SO THE DIAGONAL OF THE RHOMBUS IS 54 CM.
and then the area of the rhombus is A=p*q/2
then A=180*72/2
A=6480
Step-by-step explanation:
here firstly we will find out the diagonal of the rhombus where we have perimeter is 180 and one of its diagonal is 72 cm then by using the above mentioned formula diagonal is 54 cm. After it we will find out the area of the rhombus through the formula a=p*q/2 answer will be 6480
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