Question

perimeter of a rhombus is 20cm. the length of one of its diagonal is 9 cm. find its area and length of the other diagonal.​

Answer 1

Step-by-step explanation:

perimeter of rhombus=20cm

4×side=20cm

side=(20/4)cm

side=5cm.

OA=1/2AC

OA=1/2×9

OA=4.5cm

in triangle AOB,

Pythagoras theorem,

(OA)^2+(OB)^2=(AB)^2

(4.5)^2+(OB)^2=(5)^2

20.25+(OB)^2=25

(OB)^2=25-20.25

OB=2.17

BD=2.17×2

BD=4.32

area of rhombus =1/2×d1xd2

=1/2×9×4.32

=19.44cm^2

Answer 2

Step-by-step explanation:

its easy you can understand easily

THANK YOU