Question

perimeter of a rhombus is 52 cm and one of its diagonals is 10 cm. Find the length of the
diagonal and the area of the rhombus.​

Answer 1

Length of the other diagonal = 24 cm and

Area pf rhombus = 120 $cm^{2}$

Step-by-step explanation:

Given,

Perimeter of Rhombus = 52 cm and  one of its diagonals = 10 cm

∴ Side of the rhombus  = $\frac{52}{4}$  = 13 cm

(∵ All the sides are equal in rhombus)

∴ Longest diagonal = 24 cm

The two diagonals bisect each other,

∴ Area pf rhombus = $\frac{1}{2}$ × First diagonal × second diagonal

= $\frac{1}{2}$ × 10 × 24

= 120 $cm^{2}$

∴ Length of the other diagonal = 24 cm and

Area pf rhombus = 120 $cm^{2}$