Question

perimeter of a right angle is 60cm and its hypotenuse is 25 cm find the area of triangle

Answer 1

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perimeter of that triangle = 60cm

the measure of hypotaneous = 25cm

then the rest sides must measure = 60-25
= 35


let one side be x
then, thw measure of the third side must be 35 - x


using pythagoras theorem

(25)^2 =(x)^2 + (35-x)^2
625 = x^2 + x^2 - 70x + 1225

x^2 + x^2 - 70x + 1225 = 625

x^2 + x^2 - 70x + 1225 -625 = 0


2 x^2 - 70x + 600 = 0
2x^2 - 40x - 30 x + 600= 0
2x (x-20) -30 ( x - 20) = 0
(x-20)(2x-30)=0


x -20 = 0
x = 20

2x -30 =0
2x =30
x = 15


so,
one of the side measure either 20 cm 15 cm

if one side measure 20cm then the other must measure 35 -20 = 15cm

and if it measured 15 cm then the other side measure 35-15 = 20 cm


so,
we will get 20cm and 15 cm as our remaining sides.

one of then will be height and the other misy be the base,
now apply the formula of area of triangle i.e
(1/2) (height)(base)
= (1/2 )(20)(15)

= 150 cm^2


so, the area of that triangle will be 150 cm^2.

Answer 2

Answer:

Step-by-step explanation:

Let a, b, c be base, height and hypotenuse respectively. You have c=25 and a+b=35 and a²+b²=c²=25². Here the area of triangle is ½ab. Then (a+b)²=35² ⇒ 2ab=35²-(a²+b²) ⇒ 2ab=4(30)(5) ⇒½ab=150. Hence area of triangle is 150 sq. units