perimeter of a square is 40 cm its one of its diagonal is 12 cm find the other diagonal and area
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Let each side of a square ABCD be x cm,whose
diagonals = AC= BD= 12cm
Area of square = x^2 sq. cm.
In right angled triangleABC,
AB^2+ BC^2 = AC^2
x^2 + x^2 = 12^2
2x^2 = 144
x^2 = 72
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