Question

Perimeter of a square room is 56 m.another room has one side 2 metre more than the first but has the same Perimeter. Find the length and breadth of the second room.

Answer 1

Hey friend....
Here is your answer....

Let the length of room = x
Let the breadth of room=y

Y = x + 2

The perimeter of room = 56
2( l + b) =56
2(x + y) =56
2(x + x + 2) =56
2( 2x + 2) =56
2x + 2=28
Divide by 2 the above eq.
x + 1 =14
x=13 cm
y=15cm
Length =13cm
Breadth =15cm

Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

$\textbf{\underline{P\;of\;Square\;Room}}$

= 56 m

$\textbf{\underline{Length}}$

$\tt{\rightarrow\dfrac{P}{4}}$

$\tt{\rightarrow\dfrac{56}{4}}$

= 14 m

$\textbf{\underline{Hence}}$

$\textbf{\underline{Length\;of\;Each\;Side}}$

= 14 m

$\textbf{\underline{Next\;room\;is\;2m\;more}}$

Assume

$\textbf{\underline{Breadth\;of\; Rectangle}}$

= p

Therefore,

$\textbf{\underline{Length\;will\;be\;p+2}}$

$\textbf{\underline{p\;of\;both\;room\;is\;same}}$

Using Formula :-

Perimeter of rectangle = 2(L + B)

56 = 2(p + p + 2)

56 = 2p + 2p + 4

56 - 4 = 4p

4p = 52

$\tt{\rightarrow p=\dfrac{52}{4}}$

p = 13 m

Hence,

$\textbf{\underline{Breadth\;of\; Rectangle}}$

= 13 m

Also

Length

13 + 2 = 15 m

Therefore,

${\boxed{\sf\:{Length\;and\;breadth\;of\;2^nd \;room = 15m\;and\;13m}}}$