Math, asked by asthashishu, 4 days ago

perimeter of a triangle in which the measures of sides of are 6m11cm, 244cm, 7m3cm​

Answers

Answered by aaryabhatt943
1

Answer:

Perimeter will be 15m 58cm

Step-by-step explanation:

perimeter of triangle=sum of all sides

=6m 11 cm+244cm+7m 3cm

=6m 11 cm+2m 44cm+7m 3cm

=15m 58cm

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Answered by preeti353615
1

Answer:

The perimeter of a triangle in which the measures of sides of are 6m11cm, 244cm, 7m3cm​ is 15 m 58 cm.

Step-by-step explanation:

The perimeter of a triangle = Sum of all three sides

So, The perimeter of a triangle =  6m11cm + 244cm + 7m 3cm​

We know that 100 cm = 1 m

6m 11cm  = 6  ×100 + 11 = 600 + 11  = 611 cm

7m 3 cm = 7  ×100 + 3 = 700 + 3 = 703 cm

The perimeter of a triangle =  611cm + 244cm + 703 cm

= ​1558 cm = 15 m 58 cm

So,  the perimeter of a triangle is 15 m 58 cm.

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