Math, asked by Smarthead2006, 5 months ago

Perimeter of a triangle is 450 m and its sides are in the ratio 13 : 12 : 5. Find the area of the

triangle and the altitude to the largest side​

Answers

Answered by sid2442
1

Answer:

area is 6750

Step-by-step explanation:

let the sides be 13x,12x and 5x

according to the condition:

13x+12x+5x=450

30x=450

x=15

sides are (13*15)=195,(12*15)=180and (5*15)=75

side=a+b+c/2

=195+180+75/2

=450/2

=225

use heron's formula

area=√s(s-a)(s-b)(s-c)

area=√225(30)(45)(150)

area=√45562500

area=6750

largest side is 195

sorry dude, I am not able to find the altitude but I hope that you understand the area logic

Answered by arpitayadav57
2

Answer:

Given:

ratio of sides = 13:12:5

and perimeter = 450m

Step-by-step explanation:

perimeter = sum of all the sides

let the sides be x

So,

13x+12x+5x=450

30x=450

x=15

Ist side's length = 13×15=195m

IInd side's length = 12×15=180m

IIIrd side's length =5×15=75m

area of triangle =√s(s-a)(s-b)(s-c)

where s=(a+b+c)/2

s=125+75+180

s=225

area=√225(225-195)(225-75)(225-180)

area=6750m²

area of triangle =1/2*(base*height)

base here will be the largest side as it is asked height to the largest side

1/2(195*h)=6750

h≈69m

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