Question

perimeter of a triangle is 6p²-4p+9 and two of it's sides are p²+2p+1 and 3p²-5p³ find the third side of the triangle

Answer 1

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Answer 2

Hi ,

Perimeter ( P ) = 6p² - 4p + 9

side ( a ) = p² + 2p + 1

Side ( b ) = 3p² - 5p³

Let the side ( c )

a + b + c = P

c = P - a - b

c = 6p²-4p+9 -(p² + 2p + 1) -(3p² - 5p³)

c = 6p²-4p+9-p²-2p-1-3p²+5p³

c = 5p³+ 6p² -p² - 3p² - 4p -2p + 9 - 1

c = 5p³ + 2p² - 6p + 8

I hope this helps you.

:)