Question

perimeter of a triangle is
${8y}^{2} - 9y + 4$
and it's two sides are
${3y}^{2} - 5y \: and \: {4y}^{2} + 12$
find it's third side ​

Answer 1

Answer:

y²-4y+2

Step-by-step explanation:

Refer to picture for complete steps

Answer 2

Step-by-step explanation:

Perimeter of the triangle = sum of three sides.

= 8y2 - 9y + 4

sum of two sides = 7y2 - 5y + 12

Therefore (8y2 - 9y + 4) - (7y2 - 5y + 12)

=8y2 - 9y + 4 - 7y2 + 5y - 12

= y2 - 4y - 8