Question

Perimeter of a triangle with vertices (0,0), (6,0), (0 8) is



24

44

14

34

​

Answer 1

Answer:

24

Step-by-step explanation:

Let the triangle be ABC where

  A(0,0) ;  B(6,0) ;  C(0,8)

AB=$\sqrt[]{(6-0)^{2} +(0-0)^{2} }=6$

BC=$\sqrt{(0-6)^{2} +(8-0)^{2} } =\sqrt{36+64} =\sqrt{100} =10$

CA=$\sqrt{(0-0)^{2}+(0-8)^{2} } =8$

Perimeter of triangle= AB + BC + CA = 6 + 10 + 8 = 24

Answer 2

Answer is 24units

Formula = √(x2 - x1)² + (y2 - y1)²

AB = (0,0) & (6,0) for which x1 = 0 & x2 = 6

similarly y1 = 0 & y2 = 0

Therefore, AB = √(6-0)² + (0-0)2 = √36 = 6

Similarly, BC = (6,0) & (0,8) for which, x1 = 6 & x2 = 0 &. y1 = 0 & y2 = 8

Therefore, AB = √(0-6)² + (8-0)² = √36 + 64 = √100 = 10

Similarly, CA = (0,8) & (0,0) for which, x1 = 0 & x2 = 0. &. y1 = 8 & y2 = 0

Therefore, CA = √(0-0)² + (0-8)² = √64 = 8

Now Perimeter of the Triangle = AB + BC + CA = 6 + 10 + 8 = 24...

Therefore Perimeter of the Triangle = 24units.