Perimeter of & a rectangle times 44 cm. Its length is breadth is 1 more than 2 times of breadth. find the sides
Answers
Let the sides of our rectangle be “a” and “b”.
The perimeter of a triangle = sum of the lengths of its side = 2a + 2b.
Area of a rectangle = length * breadth
= ab.
Perimeter = 2a + 2b = 44. Which implies that,
a + b = 22.
Area = ab = 120.
And we know,
(a - b)^2 = (a + b)^2 - 4ab
From this if we calculate the value of a - b, we can figure out the value of “a” and “b”.
(a - b)^2 = (22)^2 - 4*120
= 484 - 480 = 4.
Which implies that,
a - b = 2, or a - b = - 2.
{ Doesn't really matter because I had not defined which one is length and breadth in “a” and “b” and so their values are interchangeable }
And we had found out before that,
a + b = 22, through our perimeter.
If we solve these two equations, we get,
a = 12, b = 10.
Which is our answer.
Answer:
sides are
Step-by-step explanation:
Let breadth of the rectangle be 'b' cm.
So length of the rectangle will be 'b+2' cm.
Now
Perimeter =48
2(l+b)=48
2(b+2+b)=48
2b+2=24
2b=22
b=11 cm
l=b+2=13 cm
Then,
Area of the rectangle =lb
=13×11
=143 cm
2