Perimeter of an equilateral triangle whose one vertex is at origin and centroid at (1, 7) is equal to :
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As the triangle is equilateral and the centroid is given at the origin, then it is also he orthocenter and AD is also the altitude where G divides it in the ratio 2:1.
As the point D(a,b) lies on BC, then
a+b−2=0
If A is the point (h,k), then,
3
2a+h
=0 and
3
2b+k
=0
h=−2a and k=−2b
As AD is perpendicular to BC,
k−b
h−a
×(−1)=−1
h−a=k−b
3a=3b
a=b=1
So, h=−2 and k=−2.
pls make me brainlist brother.........
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