perimeter of an isosceles triangle is 24 cm . Length of congruent side is 13 cm less than twice the length of base of triangle.Find lenegth of congruent side and base
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let the base be x cm
then, the congruent side = 2x-13cm
and the perimeter is 25cm
A.T.Q
(2x-13)+(2x-13)+x= 24
2x-13+2x-13+x=24
5x= 24+13+13
5x = 50
x = 10
so the length of the congruent side = 2*10-13= 7
the length of the base = 10
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