Math, asked by aryanbhai30, 11 months ago

perimeter of an isosceles triangle is 42 centimetre and the base is 3/2 times of the equal sides. find the length of each side of the triangle, area of the triangle and the height of the triangle​

Answers

Answered by haridasan85
2

Isosceles triangle

perimetr=42cm

anal sides = x, x

Base=3/2x

x + x +3/2x=42

2x+2x +3x=84

7x=84

x=12

Sides:

12,12,18 cm

Area of isosceles triangle:

b/4V4a^2-b^2

18/4V4X12^2-18^2

18/4V576-324

18/4v252=18/4 x 15.87

= 71.4cm2

height of the triangle

h=2A/b=2x71.4/18=7.9cm

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