Question

perimeter of an isosceles triangle is 43/4.If one of it's equal sides is 17/6.find the third side.​

Answer 1

Step-by-step explanation:61/12is the right answer

Answer 2

Answer :-

Given :-

Perimeter of an isosceles triangle is 43/4 .

One equal side is 17/6.

To Find :-

Third side.

Solution :-

If one of the equal side of an isosceles triangle is 17/6, then the other equal side will also be 17/6.

Let the third side be x.

According To Question :-

$\implies{\sf{\dfrac{17}{6} + \dfrac{17}{6} + x = \dfrac{43}{4}}}$

$\implies{\sf{\dfrac{34}{6} + x = \dfrac{43}{4}}}$

$\implies{\sf{x = \dfrac{34}{6} - \dfrac{43}{4}}}$

$\implies{\sf{x = \dfrac{129 - 68}{12}}}$

$\implies{\sf{x = \dfrac{61}{12}}}$

Verification :-

Take L.H.S :-

$\implies{\sf{\dfrac{17}{12} + \dfrac{17}{12} + \dfrac{61}{12}}}$

$\implies{\sf{\dfrac{34 + 34 + 61}{13}}}$

$\implies{\sf{\dfrac{129}{12}}}$

$\implies{\sf{\dfrac{43}{4} = R.H.S.}}$

Hence, Verified !!

$\boxed{\sf{Hence,\ the\ third\ side\ is\ \dfrac{61}{12}.}}$