perimeter of an isosceles triangle is 544 cm and length of each equal side is 5/6th of length of base. Let us write by calculating the area of this triangle?
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3
Answer:13872
Step-by-step explanation:using th formula of a triangle
Answered by
5
AB = AC = 5/6BC
AB + BC + AC = 544
5/6BC + 5/6BC + BC = 544
5BC + 5BC + 6BC / 6 = 544
16BC/6 = 544
BC = 544 * 6 / 16
AB = AC = 5/6 * 204 = 170 cm
Area of triangle ABC = b/4√4a² - b² [a is the side , b is the base]
=204/4 √4(170)² - (204)²
=51√11560 -41616
=51 * √73984
=51 * 272
=13872 cm²
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