Question

Perimeter of arectangle is 48cm and its width is 9cms calculate its area

Answer 1

perimeter=2(l+b)
48=2(9+b)
48=18+2b
30=2b
b=15
area=l×b
area=15×9
=135cm^2
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Answer 2

hey friend
here is ur answer
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perm=2×(l+b)
48=2l+2b
48=2l+2×9
=2l+18
▶▶▶
2×l=48-18=30
▶▶▶
l=30/2=15 cm
▶▶▶
area=l×b
15×9=135 cm sq.