Question

Perimeter of base of a cuboidal box is 10 m and height is 6 m. Find its area of four walls.
60 square m
16 square m
360 square m
none

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Answer 1

Step-by-step explanation:

#include<stdio.h>

#include<conio.h>

void main()

{

int a,b;

int multiplication;

clrscr();

printf("Enter the first number");

scanf("%d", &a);

printf("Enter the second number");

scanf("%d", &b);

multiplication = a*b;

printf("The Total is %d", multiplication);

getchar();

} please make branilist

Answer 2

$\mathbb{\bold{\underline{ANSWER}}}$

$\fbox{\textsf{60m ^{\textsf{2}} }}$

$\mathbb{\bold{\underline{EXPLANATION:}}}$

$\textsf{Perimeter of base: \textbf{\bold{10m}}}$

$\textsf{Height of cuboidal box: \textbf{\bold{6m}}}$

$\colon \to \textbf{To derive formulae for the values given:}$

$\star \:\texttt{Perimeter of base = 10m }$

 $\textsf{Since the box is a cuboid, so the base will be a rectangle}$

  $\bullet \textbf{ Perimeter of Rectangle = 2(l + b)}$

$\to \textbf{2(l + b) = 10m}$

$\star \texttt{ Height of Cuboid = 6m}$

$\to \textbf{h = 6m}$

$\colon \to \textbf{To find the area of four walls of the box:}$

$\textsf{Area of four walls \to L.S.A of Box}$

  $\bullet \textbf{ L.S.A of Cuboid = 2(l + b)h}$

$\star \texttt{ 2(l + b) = 10m}$

$\star \texttt{ h = 6m}$

$\to \textsf{2(l + b)h = 2(l + b) \textsf{x} h}$

$\to \textbf{10 \textsf{x} 6 = 60}$

$\therefore \bold{Area \:of \: four \: walls \: of \:the \:Cuboidal \:Box \:is: 60m ^{2} }$