Question

perimeter of isoscale triangle is 3o cm and its equal sides are length 12 cm find its area?​

Answer 1

Answer:

Isosceles triangle

Solve for area

A=bhb

2

b Base

Enter value

cm

hb Height

12

cm

Step-by-step explanation:

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Answer 2

Answer:

Perimeter of isosceles triangle=30cm

Length of equal sides=12cm

Let third side of triangle=xcm

According to problem,

x+12+12=30

x+24=30

x=30−24

x=6

∴ Third side of triangle=6cm

Using Heron's formula

Area of triangle=s(s−a)(s−b)(s−c) sq. units

where s=2a+b+c

s=230=15

Area of triangle=15(15−12)(15−12)(15−6)cm2

=15×3×3×9cm2

=3×3×15cm2

=915cm2

∴ Area of triangle=915cm2.

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