Question

perimeter of isosceles right angle triangle is (6+2√2)m. find the area of the triangle.please answer​

Answer 1

Answer:

Let a be the two equal sides of isosceles triangle.

perimeter of isosceles right angle triangle =2a+2√2a

2a(1+√2)=6+2√2

:-2a(1+√2)=2(3+√2)

hence

a=3+√2/1+√2

hence

Area =1/2*a^2

=>1/2*[(3+√2)/(1+√2)]^2