perimeter of length 20m ,breadth 15m
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Answered by
22
Given length =20 m and breadth=15
Perimeter of a rectangle is 2(l+b)
=2(20+15)
=2(35)
=70 sq.m.
Answered by
2
perimeter = 2 ( l+ b ) where l = 20. and b =15
2(20+15) = 2×35=70
so perimeter is 70sqm
2(20+15) = 2×35=70
so perimeter is 70sqm
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