Math, asked by ananyasj606, 2 months ago

perimeter of rectangle
28. How many times a wheel of radius 35cm must rotate to go 352cm? Also find the
area of the wheel​

Answers

Answered by jackzzjck
11

SOLUTION

Radius of the wheel = 35cm.

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 35\ cm}\end{picture}

Total distance traveled by the wheel = 352cm.

\boxed{\sf Number \: of\:  rotation\:  made\:  by \: the \: wheel = \dfrac{Total \; distance \;covered}{Distance \: covered\:  in \: one\:  rotation} }

Distance covered in one rotation = 2πr , Where r is the radius of the circle.

\implies \sf Distance \: covered \;in \;one\; rotation = 2* \dfrac{22}{7} * 35

\implies \sf Distance \: covered \;in \;one\; rotation = 2* 22* 5

\implies \sf Distance \: covered \;in \;one\; rotation = 220cm.

Therefore,

\sf Number \: of\:  rotation\:  made\:  by \: the \: wheel = \dfrac{352}{220}

\implies Number of rotation made by the wheel = 1.6.

AREA

Area of a circle = πr² , Where r is the radius of the circle.

Here,

r = 35cm.

\implies \sf Area \: of \: the \: circle = \dfrac{22}{7}*(35)^2

\implies \sf Area \: of \: the \: circle = \dfrac{22}{7}*1225

\implies \sf Area \: of \: the \: circle = 22 * 175

\implies Area of the circle = 3850 cm².

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